alloc-util: avoid allocating zero size memory blocks
It's not clear what libc's make of this. We clamp to 1 byte allocations in most cases already, let's add this for a few where this was missing.
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@ -27,7 +27,7 @@ typedef void (*free_func_t)(void *p);
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size_t _n_ = n; \
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assert(!size_multiply_overflow(sizeof(t), _n_)); \
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assert(sizeof(t)*_n_ <= ALLOCA_MAX); \
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(t*) alloca(sizeof(t)*_n_); \
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(t*) alloca((sizeof(t)*_n_) ?: 1); \
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})
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#define newa0(t, n) \
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@ -35,14 +35,14 @@ typedef void (*free_func_t)(void *p);
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size_t _n_ = n; \
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assert(!size_multiply_overflow(sizeof(t), _n_)); \
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assert(sizeof(t)*_n_ <= ALLOCA_MAX); \
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(t*) alloca0(sizeof(t)*_n_); \
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(t*) alloca0((sizeof(t)*_n_) ?: 1); \
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})
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#define newdup(t, p, n) ((t*) memdup_multiply(p, sizeof(t), (n)))
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#define newdup_suffix0(t, p, n) ((t*) memdup_suffix0_multiply(p, sizeof(t), (n)))
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#define malloc0(n) (calloc(1, (n)))
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#define malloc0(n) (calloc(1, (n) ?: 1))
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static inline void *mfree(void *memory) {
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free(memory);
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@ -65,7 +65,7 @@ void* memdup_suffix0(const void *p, size_t l); /* We can't use _alloc_() here, s
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void *_q_; \
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size_t _l_ = l; \
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assert(_l_ <= ALLOCA_MAX); \
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_q_ = alloca(_l_); \
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_q_ = alloca(_l_ ?: 1); \
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memcpy(_q_, p, _l_); \
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})
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@ -135,7 +135,7 @@ void* greedy_realloc0(void **p, size_t *allocated, size_t need, size_t size);
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char *_new_; \
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size_t _len_ = n; \
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assert(_len_ <= ALLOCA_MAX); \
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_new_ = alloca(_len_); \
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_new_ = alloca(_len_ ?: 1); \
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(void *) memset(_new_, 0, _len_); \
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})
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@ -146,7 +146,7 @@ void* greedy_realloc0(void **p, size_t *allocated, size_t need, size_t size);
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size_t _mask_ = (align) - 1; \
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size_t _size_ = size; \
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assert(_size_ <= ALLOCA_MAX); \
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_ptr_ = alloca(_size_ + _mask_); \
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_ptr_ = alloca((_size_ + _mask_) ?: 1); \
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(void*)(((uintptr_t)_ptr_ + _mask_) & ~_mask_); \
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})
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