e79d0b59c8
When running journalctl --user-unit=foo as an unprivileged user we could get
the usual hint:
Hint: You are currently not seeing messages from the system and other users.
Users in groups 'adm', 'systemd-journal', 'wheel' can see all messages.
...
But with --user-unit our filter is:
(((_UID=0 OR _UID=1000) AND OBJECT_SYSTEMD_USER_UNIT=foo.service) OR
((_UID=0 OR _UID=1000) AND COREDUMP_USER_UNIT=foo.service) OR
(_UID=1000 AND USER_UNIT=foo.service) OR
(_UID=1000 AND _SYSTEMD_USER_UNIT=foo.service))
so we would never see messages from other users.
We could still see messages from the system. In fact, on my machine the
only messages with OBJECT_SYSTEMD_USER_UNIT= are from the system:
journalctl $(journalctl -F OBJECT_SYSTEMD_USER_UNIT|sed 's/.*/OBJECT_SYSTEMD_USER_UNIT=\0/')
Thus, a more correct hint is that we cannot see messages from the system.
Make it so.
Fixes #7887.
30 lines
1 KiB
C
30 lines
1 KiB
C
/* SPDX-License-Identifier: LGPL-2.1+ */
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/***
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This file is part of systemd.
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Copyright 2013 Zbigniew Jędrzejewski-Szmek
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Copyright 2015 Lennart Poettering
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systemd is free software; you can redistribute it and/or modify it
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under the terms of the GNU Lesser General Public License as published by
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the Free Software Foundation; either version 2.1 of the License, or
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(at your option) any later version.
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systemd is distributed in the hope that it will be useful, but
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WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
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Lesser General Public License for more details.
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You should have received a copy of the GNU Lesser General Public License
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along with systemd; If not, see <http://www.gnu.org/licenses/>.
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***/
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#include <stdbool.h>
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#include <sys/types.h>
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#include "sd-journal.h"
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bool journal_field_valid(const char *p, size_t l, bool allow_protected);
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int journal_access_check_and_warn(sd_journal *j, bool quiet, bool want_other_users);
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