8442f0d966
When fnmatch processes a bracket expression, and eventually finds it to be unterminated, it should rescan it, treating the starting bracket as a normal character. That didn't happen when a matching character was found while scanning the bracket expression.
38 lines
1.4 KiB
C
38 lines
1.4 KiB
C
/* Test for fnmatch handling of unterminated bracket expression (bug 28792)
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Copyright (C) 2022 Free Software Foundation, Inc.
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This file is part of the GNU C Library.
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The GNU C Library is free software; you can redistribute it and/or
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modify it under the terms of the GNU Lesser General Public
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License as published by the Free Software Foundation; either
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version 2.1 of the License, or (at your option) any later version.
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The GNU C Library is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
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Lesser General Public License for more details.
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You should have received a copy of the GNU Lesser General Public
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License along with the GNU C Library; if not, see
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<https://www.gnu.org/licenses/>. */
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#include <fnmatch.h>
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#include <support/check.h>
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static int
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do_test (void)
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{
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/* An unterminated bracket expression should be rescanned, treating the
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open bracket as a normal character. The backslash causes the close
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bracket to be treated as a normal character, not ending the bracket
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expression. */
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TEST_VERIFY (fnmatch ("[", "[", 0) == 0);
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TEST_VERIFY (fnmatch ("[[", "[[", 0) == 0);
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TEST_VERIFY (fnmatch ("[\\]", "[]", 0) == 0);
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TEST_VERIFY (fnmatch ("[[\\]", "[[]", 0) == 0);
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return 0;
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}
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#include <support/test-driver.c>
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